0.25x^2+8.5x-17=0

Solution for 0.25x^2+8.5x-17=0 equation:

0.25x^2+8.5x-17=0

a = 0.25; b = 8.5; c = -17;
Δ = b2-4ac
Δ = 8.52-4·0.25·(-17)
Δ = 89.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.5)-\sqrt{89.25}}{2*0.25}=\frac{-8.5-\sqrt{89.25}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.5)+\sqrt{89.25}}{2*0.25}=\frac{-8.5+\sqrt{89.25}}{0.5}
$